expanding:
(2x+1/6)(2x+1/6)
4x^2+x/3+x/3+1/36
combining like terms:
3x^2+2x/3+1/36
i hope this helped! please correct me if i am wrong:)
I think you made a typo :)
The answer is 4x^2+2/3x+1/36, not 3x^2+2/3x+1/36
(Latexed)
\((2x+\frac{1}{6})(2x+\frac{1}{6})\)
Multiply
\(4x^2+\frac{2}{3}x+\frac{1}{36}\)
Annnd that's your answer!