+0  
 
0
243
1
avatar+284 

Complete the coordinate proof of the theorem.

Given:  ABCD is a square.

Prove: The diagonals of ​ ABCD ​ are perpendicular.

 

 

Enter your answers in the boxes.

 

The coordinates of  square ABCD are A(0, 0) , B(________, 0), C(_____, a), and ​ D(0,  a) .

 

The slope of AC¯¯¯¯¯ , when simplified, is equal to_________ .

 

The slope of BD¯¯¯¯¯, when simplified, is equal to −1 .

 

The product of the slopes is equal to ____________.

 

Therefore, the diagonals of ​ ABCD ​ are perpendicular.

sii1lver  Jan 7, 2018

Best Answer 

 #1
avatar+7266 
+1

The coordinates of square ABCD are  A(0, 0) ,  B(a, 0) ,  C(a a) , and ​ D(0,  a) .

 

The slope of  AC   =   [a - 0] / [a - 0]   =   1 .

 

The slope of  BD   =   -1 .

 

The product of the slopes   =   1 * -1   =   -1 .

hectictar  Jan 7, 2018
 #1
avatar+7266 
+1
Best Answer

The coordinates of square ABCD are  A(0, 0) ,  B(a, 0) ,  C(a a) , and ​ D(0,  a) .

 

The slope of  AC   =   [a - 0] / [a - 0]   =   1 .

 

The slope of  BD   =   -1 .

 

The product of the slopes   =   1 * -1   =   -1 .

hectictar  Jan 7, 2018

31 Online Users

avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.