+0  
 
0
277
1
avatar+295 

sin(t)cos(t)[sec(t)-csc(t)]=

 

A. sin(t)-cos(t)

B. sec(t)-csc(t)

C. 2sin(t)cos(t)

D. sec^2(t)-csc^2(t)

E. None of the above

Deathstroke_rule  Apr 25, 2017
 #1
avatar+92805 
+2

sin(t)cos(t)[sec(t)-csc(t)]=

 

\(sin(t)cos(t)[sec(t)-csc(t)]\\ =sin(t)cos(t)[\frac{1}{cos(t)}-\frac{1}{sin(t)}]\\ =\frac{sin(t)cos(t)}{cos(t)}-\frac{sin(t)cos(t)}{sin(t)}\\ =sin(t)-cos(t)\)

Melody  Apr 25, 2017

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