complete the proof of the polynomial identity.

Question

0

795

1

+68

(x^2+y^2)^2+2x^2y^2-y^4=x^2(x^2+4y^2)

Step-by-step instructions please, thank you!

Love2Read Jan 16, 2019

Melody · Answer 1 · 2019-01-17T10:37:27

(x^2+y^2)^2+2x^2y^2-y^4=x^2(x^2+4y^2)

$(x^2+y^2)^2+2x^2y^2-y^4=x^2(x^2+4y^2)\\$

$LHS\\=x^4+y^4+2x^2y^2+2x^2y^2-y^4\\ =x^4+4x^2y^2\\ =x^2(x^2+4y^2)\\ =RHS\\~\\ QED$