So, I've got this:
A shot putter makes a good put and the ball is h meters above the ground, when it has traveled s meters horizontally.
The path of the ball can be described with: h(s)= -0,004s2+0,64s+1,94
How long is the put?
Am I supposed to somehow complete the square, since the latter looks like that?
If so, how? {nl}
I'm thankful for answers!
Edit: Do I have to multiply everything with -250 to make it s^2 only?
+129840 We are solving this : [ the shot will be at 0 m above the ground at the finish ]
-0.004s^2 +0.64s+1.94 = 0 multiply by -250
s^2 - 160s - 485 = 0 add 485 to each side
s^2 - 160s = 485
Take 1/2 of 160 [80] ......... square it [6400] and add to each side
s^2 - 160s + 6400 = 485 + 6400 factor the left side and simplify the right
(s - 80)^2 = 6885 take the + √ root
s - 80 = √6885 add 80 to boh sides
s = √6885 + 80 ≈ 162.98 m [ that's one heck of a throw....LOL !!! ]
