#1**+1 **

**completely factor this expression?**

**6m^2n - 12mn^2 - 10mn + 20n^2**

**\(\begin{array}{|rcll|} \hline && 6m^2n - 12mn^2 - 10mn + 20n^2 \\ &=& 2n ( 3m^2 - 6mn - 5m + 10n) \\ &=& 2n (m-2n) (3m-5) \\ \hline \end{array}\)**

heureka Jul 20, 2017

#2**0 **

Factor the following:

6 m^2 n - 12 m n^2 - 10 m n + 20 n^2

Factor 2 n out of 6 m^2 n - 12 m n^2 - 10 m n + 20 n^2:

2 n (3 m^2 - 6 m n - 5 m + 10 n)

Factor terms by grouping. 3 m^2 - 6 m n - 5 m + 10 n = (10 n - 6 m n) + (3 m^2 - 5 m) = m (3 m - 5) - 2 n (3 m - 5):

2 n m (3 m - 5) - 2 n (3 m - 5)

Factor 3 m - 5 from m (3 m - 5) - 2 n (3 m - 5):

**Answer: | 2n (3m - 5) (m - 2n)**

Guest Jul 20, 2017