+118723 \(-2x^2+3x-4=0\\ \mbox{divide through by -2}\\ x^2-\frac{3}{2}\;x+2=0\\ x^2-\frac{3}{2}\;x=-2\\ x^2-\frac{3}{2}\;x+\left(\frac{3}{4}\right)^2=-2+\left(\frac{3}{4}\right)^2\\ \left(x-\frac{3}{4}\right)^2=\frac{-23}{16}\\ \mbox{No solution in the real number system} \)
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