Let
f(z) = z^2 if z is real
f(z) = z + 1 if z is not real
Find f(i)+f(1)+f(-1)+f(-i).
f(i): i+1
f(1): 1^2 = 1
f(-1): -1^2 = -1
f(-i): -i+1
So we got...
(i+1)+1+(-1)+(-i+1) = 2
-Vinculum