If $Q = 11-5i$, $E = 11+5i$, and $D = 2i$, find $Q\cdot E \cdot D$.
\((Q)(E)(D) = (11-5i)(11+5i)(2i) = (121 + 25)(2i) = (146)(2i) = \boxed{292i}\)
(using difference of squares)
By the way, are you three people in the same class or one person with two alternate accounts?