Solve for $z$ in the following equation: $2-iz = 1 + 3iz$.
[i]Express your answer in standard form[/i].
Solve for z in the following equation: 2−iz=1+3iz.
2−iz=1+3iz2−1−iz−3iz=01−4iz=0|×i1∗i−4i2z=0i−4i2z=0|i2=−1i−4(−1)z=0i+4z=04z=−iz=−i4