+0  
 
0
35
1
avatar

Suppose that a and b are positive integers such that (a-bi)^2 = 8 - 6i + 13 - 4i. What is a-bi?

 Jun 20, 2021
 #1
avatar+2109 
0

 (a-bi)^2 = 8 - 6i + 13 - 4i

a^2 - b^2 - 2abi = 21 - 10i

 

-2abi = -10i

ab = 5

a^2 - b^2 = 21

 

Can you take it from here?

 

=^._.^=

 Jun 20, 2021

23 Online Users

avatar