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Describe all solutions to zw - 3w - 2iw + 4z = 7iw + 5w + 11iz - 13 + 15i

where z and w are complex numbers.

 Dec 24, 2022
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cool.

 

Let's say that z = a+bi and w = c+di

okokok

\( zw - 3w - 2iw + 4z = 7iw + 5w + 11iz - 13 + 15i\)

\(= (a+bi)(c+di) - 3(c+di) - 2i(c+di) + 4(a+bi) = 7i(c+di) + 5(c+di) + 11i(a+bi) - 13 + 15i\)

so then...

\(= ac+adi+bci-bd - 3c-3di - 2ic-2di^2 + 4a+4bi = 7ic+7di + 5c+5di + 11ia+11bi^2 - 13 + 15i\)

This is not the correcr way to do it oh gosh...

\(= ac+adi+bci-bd -2di^2 + 4a+4bi = 9ic+15di + 8c + 11ia+11bi^2 - 13 + 15i\)

 

\( ac-bd+ 4a =+ 8c +(11b^2-4b-bc-ad+2di+9c+15d+11a+15)i - 13\)

yeahhhh..... Im not the one solving this

 Dec 24, 2022

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