complex numbers

When

$x = \dfrac{3 + 5i}{2}$,

find the value of  $2x^3 + 2x^2 - 7x + 72$.

$\begin{array}{|rcll|} \hline x^2 &=& \left(\dfrac{3 + 5i}{2}\right)^2 \\\\ x^2 &=& \dfrac{(3 + 5i)^2}{4} \\\\ x^2 &=& \dfrac{9+30i-25}{4} \\\\ x^2 &=& \dfrac{-16+30i}{4} \\\\ \mathbf{x^2} &=& \mathbf{\dfrac{-8+15i}{2}} \\ \hline \end{array} \begin{array}{|rcll|} \hline x^3 &=& \dfrac{(-8+15i)}{2}*\dfrac{(3 + 5i)}{2} \\\\ x^3 &=& \dfrac{(-8+15i)(3 + 5i)}{4} \\\\ x^3 &=& \dfrac{-24-40i+45i-75}{4} \\\\ x^3 &=& \dfrac{-99+5i}{4} \\\\ \mathbf{x^3} &=& \mathbf{\dfrac{-99+5i}{4}} \\ \hline \end{array}$

$\begin{array}{|rcll|} \hline \mathbf{2x^3 + 2x^2 - 7x + 72} &=& 2*\dfrac{(-99+5i)}{4} + 2*\dfrac{(-8+15i)}{2} - 7*\dfrac{(3 + 5i)}{2} + 72 \\\\ &=& \dfrac{-99+5i}{2} + (-8+15i)- \dfrac{7(3 + 5i)}{2} + 72 \\\\ &=& \dfrac{-99+5i}{2} -8+15i- \dfrac{21 + 35i}{2} + 72 \\\\ &=& \dfrac{-99+5i}{2} - \dfrac{21 + 35i}{2} + 64 +15i \\\\ &=& \dfrac{-99+5i-(21 + 35i)}{2} + 64 +15i \\\\ &=& \dfrac{-99+5i-21 - 35i}{2} + 64 +15i \\\\ &=& \dfrac{-120-30i}{2} + 64 +15i \\\\ &=& -60-15i + 64 +15i \\\\ &=& \mathbf{4} \\ \hline \end{array}$