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Find all complex numbers z such that z^2 = \(2i + 2\).

 Jan 18, 2022
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We can say z=a+bi, so z^2 is a^2-b^2+2abi. For our original equation to be true, a^2-b^2=2 and ab=1. Try solving the problem from there.

 Jan 18, 2022

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