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The value of (1 + i)^16 is a positive real number.  What is it?

 Jan 20, 2022
 #1
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(1+i)^2 = 1-1+2i = 2i

 

(1+i)^4 = (2i)^2 = -4

 

(1+i)^8 =(-4)^2 = 16

 

(1+i)^16= 16^2 = 256

 

I don't know why you needed any help with that.

 Jan 20, 2022

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