The value of (1 + i)^16 is a positive real number. What is it?
(1+i)^2 = 1-1+2i = 2i
(1+i)^4 = (2i)^2 = -4
(1+i)^8 =(-4)^2 = 16
(1+i)^16= 16^2 = 256
I don't know why you needed any help with that.