Substituting for the values of a and b we get: \((4-2i+7)-2(3+2i-5i)\)
Simplifying, we get: \(\color{brown}\boxed{4i+5}\)
You can just assume i as a variable, because you can't really do anything with it
Substituting for the values of a and b we get: \((4-2i+7)-2(3+2i-5i)\)
Simplifying, we get: \(\color{brown}\boxed{4i+5}\)