Simplify $\dfrac{5+12i}{2-8i}$. Your answer should be of the form $a+bi$, where $a$ and $b$ are both real numbers and written as improper fractions (if necessary).
\(\frac{5+12i}{2-8i} \cdot \frac{2+8i}{2+8i} = \frac{10+24i+40i+96i^2}{70} = \boxed{\frac{-43+32i}{35}}\)
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