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There are 3 complex numbers a + bi c + di, and e + fi. If b = 2, e = -a - c, and the sum of the numbers is 3i, find d + f.

 Mar 5, 2021
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 a + bi + c + di + e + fi = 3i

(a+c+e) + (b+d+f)i = 3i

(a+c+-a - c) + (b+d+f)i = 3i

(b+d+f)i = 3i

b+d+f = 3

2+d+f = 3

d+f = 1

 

I hope this helped. :))

=^._.^=

 Mar 5, 2021

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