There are 3 complex numbers a + bi c + di, and e + fi. If b = 2, e = -a - c, and the sum of the numbers is 3i, find d + f.
a + bi + c + di + e + fi = 3i
(a+c+e) + (b+d+f)i = 3i
(a+c+-a - c) + (b+d+f)i = 3i
(b+d+f)i = 3i
b+d+f = 3
2+d+f = 3
d+f = 1
I hope this helped. :))
=^._.^=
