Compute (1 + i)/(2 - i)(3 + i).
\({(1 + i)\over{(2-i)}}*(3+i)=2i\)
Or, if your problem specifies the order of operations differently:
\({(1 + i)\over{(2 - i)(3 + i)}}={1 + i\over{7-i}}={8+6i\over50}={4\over25} + {3\over25}i\)
