Use compositions of functions to determine wether the function in each pair are inverse functions.
a) y=1/3x +2 and y=3x-6 b) y=2x -3 and y= 2x+3
In understand how to find an inverse function but I am not sure what this exercise mean and how to solve. Thanks for the clarification and the answer in advance :).
+130513 a) y=1/3x +2 and y=3x-6
Here's another way to do this.....we put the second function into the first and evaluate.......if we get "x" back out, we then put the first function into the second and see if we again get "x" returned again......if we get an "x" in both cases, they are inverse functions.....it's easier to do than explain!!!...so we have
The second function put into the first:
(1/3)(3x -6) + 2 = x - 2 + 2 = x so far, so good
The first function put into the second:
3[1/3)x + 2] - 6 = x + 6 - 6 = x
Yep....they're inverses.....the order in which we do this doesn't matter......we could have done the second thing first.......Note......if we don't get an "x" out in the first step, there's no reason to do the second........thet will not be inverses........we have to get an "x" returned in both cases !!!
Hope this helps.......!!!!!.
