Let's see if we can discover a pattern....
1/3 + 1/12 + 1/30 + 1/60 + 1/105.....
1/(3*1) + 1/(6*2) + 1/(10*3) + 1/(15*4) + 1/(21*5)......
The form is
∑1/((n)(n+1)(n-1)/2) = ∑2/((n)(n+1)(n-1)) for n=2 to n=infinity
And WolframAlpha gives this sum as 1/2
