+218 Compute
\(1 + \frac{3}{6} + \frac{5}{6^2} + \frac{7}{6^3} + \dotsb.\)
+239 This is a geometric series with first term 1 and common ratio 61. Since the absolute value of the common ratio is less than 1, the
series converges.
We can compute the sum of a geometric series using the following formula:
S=1−ra1
where a1 is the first term and r is the common ratio.
In this case, we have a1=1 and r=61, so the sum of the series is:
S = 1/(1 - 1/6) = 1/(5/6) = 6/5.
