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Compute \(\sum_{n=1}^{\infty} \frac{3n-1}{2^n}.\)

Guest May 2, 2019

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\(\sum_{n=1}^{\infty} \frac{3n-1}{2^n} = 5\)

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Anthrax May 2, 2019

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Best Answer

\(\sum_{n=1}^{\infty} \frac{3n-1}{2^n} = 5\)

Anthrax May 2, 2019

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