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Concrete can be purchased by the cubic yard. How much will it cost to pour a slab 17 feet by 17 feet by 2 inches for a patio if the concrete costs $40.00 per cubic yard?

 Apr 10, 2015

Best Answer 

 #2
avatar+118724 
+5

Hi anon,

Your basic logic is good but you have muddled up all your units.

You have feet inches and yards and you have treated them like they are all the same.

Concrete can be purchased by the cubic yard. How much will it cost to pour a slab 17 feet by 17 feet by 2 inches for a patio if the concrete costs $40.00 per cubic yard?

Since the final price is per cubic yard, I might convert everthing to yards from the beginning.

17 feet = $${\frac{{\mathtt{17}}}{{\mathtt{3}}}}$$      yards

 

2 inches =  $${\frac{{\mathtt{2}}}{\left({\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{3}}\right)}}$$     yards

 

So the cost will be

$${\mathtt{40}}{\mathtt{\,\times\,}}\left({\frac{{\mathtt{17}}}{{\mathtt{3}}}}\right){\mathtt{\,\times\,}}\left({\frac{{\mathtt{17}}}{{\mathtt{3}}}}\right){\mathtt{\,\times\,}}\left({\frac{{\mathtt{2}}}{\left({\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{3}}\right)}}\right) = {\frac{{\mathtt{5\,780}}}{{\mathtt{81}}}} = {\mathtt{71.358\: \!024\: \!691\: \!358\: \!024\: \!7}}$$

 

=   $71.36

 Apr 10, 2015
 #1
avatar
0

I'm going to take a good guess on this

17*17=289

289*2= 578

578*40=23120

 Apr 10, 2015
 #2
avatar+118724 
+5
Best Answer

Hi anon,

Your basic logic is good but you have muddled up all your units.

You have feet inches and yards and you have treated them like they are all the same.

Concrete can be purchased by the cubic yard. How much will it cost to pour a slab 17 feet by 17 feet by 2 inches for a patio if the concrete costs $40.00 per cubic yard?

Since the final price is per cubic yard, I might convert everthing to yards from the beginning.

17 feet = $${\frac{{\mathtt{17}}}{{\mathtt{3}}}}$$      yards

 

2 inches =  $${\frac{{\mathtt{2}}}{\left({\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{3}}\right)}}$$     yards

 

So the cost will be

$${\mathtt{40}}{\mathtt{\,\times\,}}\left({\frac{{\mathtt{17}}}{{\mathtt{3}}}}\right){\mathtt{\,\times\,}}\left({\frac{{\mathtt{17}}}{{\mathtt{3}}}}\right){\mathtt{\,\times\,}}\left({\frac{{\mathtt{2}}}{\left({\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{3}}\right)}}\right) = {\frac{{\mathtt{5\,780}}}{{\mathtt{81}}}} = {\mathtt{71.358\: \!024\: \!691\: \!358\: \!024\: \!7}}$$

 

=   $71.36

Melody Apr 10, 2015

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