A cone has a surface area of 360*pi in^2 and volume 800*pi in^3. The cone is dilated, and the surface area of the dilated coin is 2,250*pi in^2. What is the dilated cone's volume?
Each dimension of the dilated cone will have a scale factor of sqrt [ (2250 / 360)] = sqrt (6.25) = 2.5
So...the dilated cone's volume = 800pi * (2.5)^3 = 12500 pi (in^3)