A 288 degree circular sector with radius 18 is rolled to form a cone. Find the height of the cone.
A 288 degree circular sector with radius 18 is rolled to form a cone. Find the height of the cone.
the slant height will be 18
The circumference at the base will be \(\frac{288}{360}*2\pi*18\)
\(C=2\pi r\\ \frac{288}{360}*2\pi*18=2\pi r\\ \frac{288}{360}*18= r\\ r=14.4\;units\\~\\ \)
Check my working then use pythagoras's Theorem to find the height