The problem is:
Find the set of values \(a\) for which the range of the function
\(f(x) = \frac{x^2 + a}{x + 1}\)
is the set of all real numbers.
I got \([-1 , ∞)\) by finding x in terms of y and a, then finding when that x value would be real.
[-1.inf) is correct. Good job!
Oh, it was incorrect for some reason.
I got it right :)
Find the set of values a for which the range of the function
\(f(x) = \frac{x^2 + a}{x + 1} \)
Hello Guest!
\(a\in \mathbb R\ |\ a\neq -1\)
!