+0

+1
157
4

The problem is:

Find the set of values $$a$$ for which the range of the function

$$f(x) = \frac{x^2 + a}{x + 1}$$

is the set of all real numbers.

I got $$[-1 , ∞)$$ by finding x in terms of y and a, then finding when that x value would be real.

May 31, 2021

#1
+1

[-1.inf) is correct.  Good job!

May 31, 2021
#2
0

Oh, it was incorrect for some reason.

Guest May 31, 2021
#3
0

I got it right :)

Guest May 31, 2021
#4
+13045
+1

Find the set of values a for which the range of the function

$$f(x) = \frac{x^2 + a}{x + 1}$$

is the set of all real numbers.

Hello Guest!

$$a\in \mathbb R\ |\ a\neq -1$$

!

May 31, 2021