The problem is:

Find the set of values \(a\) for which the range of the function

\(f(x) = \frac{x^2 + a}{x + 1}\)

is the set of all real numbers.

I got \([-1 , ∞)\) by finding x in terms of y and a, then finding when that x value would be real.

[-1.inf) is correct. Good job!

Oh, it was incorrect for some reason.

I got it right :)

Find the set of values a for which the range of the function

\(f(x) = \frac{x^2 + a}{x + 1} \)

Hello Guest!

\(a\in \mathbb R\ |\ a\neq -1\)

!