Solve \($\frac{1}{3} t - 5 < t - 2 \le -3t + 7.$\) Give your answer as an interval.
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+14903 Solve \(\frac{1}{3} t - 5 < t - 2 \le -3t + 7\). Give your answer as an interval.
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\(\frac{1}{3} t - 5 < t - 2 \le -3t + 7\)
\(t_{intervals}\in\{-4.5,\ 2.25,\ 3.6\}\)
LaTeX is going crazy again.
1/3 t - 5 < t - 2 <= - 3t + 7
1/3 t - 5 < t - 2
- ∞ < t < - 4.5
t - 2 <= - 3t + 7
- ∞ < t <= 2.25
1/3 t - 5 <= - 3t + 7
- ∞ < t <= 3.6
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