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Solve \($\frac{1}{3} t - 5 < t - 2 \le -3t + 7.$\)  Give your answer as an interval.

 

Thanks if you help

 Nov 10, 2020
 #1
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Solve  \(\frac{1}{3} t - 5 < t - 2 \le -3t + 7\).  Give your answer as an interval.

 

Hello Guest!

 

\(\frac{1}{3} t - 5 < t - 2 \le -3t + 7\)

 

\(t_{intervals}\in\{-4.5,\ 2.25,\ 3.6\}\)

 

 

LaTeX is going crazy again.

 

1/3 t - 5 < t - 2 <= - 3t + 7

 

 

1/3 t - 5 < t - 2

- ∞ < t < - 4.5

 

 

 t - 2 <= - 3t + 7

- ∞ < t <= 2.25

 

 

1/3 t - 5 <= - 3t + 7

- ∞ < t <= 3.6

laugh  !

 Nov 11, 2020
edited by asinus  Nov 11, 2020
edited by asinus  Nov 11, 2020
edited by asinus  Nov 11, 2020
edited by asinus  Nov 11, 2020
edited by asinus  Nov 11, 2020

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