A coin is tossed 10 times, and at least 8 of the tosses were heads. How many different sequences of tosses could there have been?
At least 8 means that either 8, 9 or 10 heads were tossed
So we have
C(10, 8) + C(10,9) + C(10,10) =
45 + 10 + 1 =
56 possible sequences