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Let G be the center of equilateral triangle XYZ. A dilation centered at G with scale factor -4/3 is applied to triangle XYZ, to obtain triangle X'Y'Z'. Let A be the area of the region that is contained in both triangles XYZ and X'Y'Z'. Find A/[XYZ].

 Jan 24, 2021
 #1
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Similar question:  https://web2.0calc.com/questions/help_54234#r3

 Jan 25, 2021
 #2
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If I'm not mistaken, the answer is:  A / [XYZ] = 851/999

 Jan 25, 2021

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