Remove the integers which are congruent to 3 (mod 7) from the following list of five integers, and sum the integers that remain.\(85 \qquad 49,\!479 \qquad -67 \qquad 12,\!000,\!003 \qquad -3\)
85 mod 7 =1 Keep
49,479 mod 7 = 3 Remove
-67 mod 7 =3 Remove
12,000,003 mod 7 =1 Keep
-3 mod 7 = 4 Keep
[85 +12,000,003 - 3] =12,000,085
There is more than one answer for this.
for instance:
-3 mod 7 does equal -3 but it also equals 4. Which one do you want?
Maybe it is mod 7 of the result that is wanted. In which case there would be only one answer.
+28 
