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 Dec 4, 2018
edited by YEEEEEET  Dec 4, 2018
 #1
avatar+27361 
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Hyperbola C2:  \(\frac{(x-a)^2}{9}-\frac{(y-0)^2}{4}=1\)

 

On the x-axis y = 0, and the values of x are: \(x = a\pm3\) so \(x=a\) is the value half way between the two parts of the curve.

 

The two asymptotes cross at this half-way point, so from \(y=\frac{2}{3}x-2\) we have \(x = 3\) when y = 0.  

 

So \(a = 3\)

 

.
 Dec 5, 2018
edited by Alan  Dec 5, 2018

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