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# Conic section

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Dec 4, 2018
edited by YEEEEEET  Dec 4, 2018

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Hyperbola C2:  $$\frac{(x-a)^2}{9}-\frac{(y-0)^2}{4}=1$$

On the x-axis y = 0, and the values of x are: $$x = a\pm3$$ so $$x=a$$ is the value half way between the two parts of the curve.

The two asymptotes cross at this half-way point, so from $$y=\frac{2}{3}x-2$$ we have $$x = 3$$ when y = 0.

So $$a = 3$$

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Dec 5, 2018
edited by Alan  Dec 5, 2018