how do you graph (x-16)^2=(1/2)(y-8)?? Obviously this is a parabola and the vertex is (16,8) but where do I go from there?? What is the focus etc? How do I know what the rest of the points are on the graph?
+118658 how do you graph (x-16)^2=(1/2)(y-8)?? Obviously this is a parabola and the vertex is (16,8) but where do I go from there?? What is the focus etc? How do I know what the rest of the points are on the graph?
This is of the form
\((x-h)^2=4a(y-k)\\ h=16,k=8,a=1/8\\ (x-16)^2=4*\frac{1}{8}(y-8)\\ Vertex\;\;(16,8)\\ focal\; length =\frac{1}{8} \text { so focus is }(16,8.125)\\ Latus\;r****m\;is\; 4a=0.5\; units \;long\;\\\ \text{so the ends of the latus r****m are }(16-0.25,8.125)\;\;and\;\;(16+0.25,8.125)\\ \text{i.e. two more points on the graph are }(15.75,8.125)\;\;and\;\;(16.25,8.125)\\ \)
Here is the graph :)
Any questions? Just ask. :)
