Mañana tengo exámen y no entiendo como se hacen las potencias de los numeros imaginarios. HEEEEELP ME!!!!
Es este: (-2-4i) ^ 2
Se el resultado pero no se como es el procedimiento para realizar el ejercio!!!! Ayudaa
+118609 It is this: (- 2 - 4i) ^ 2
Is the result but not be as it is the procedure for the exercise! Ayudaa
by Anonymous (3 hours ago)
This is just a perfect square
$$(a+b)^2=a^2+2ab+b^2$$
--------------------------------
$$\begin{array}{rll}
(-2-4i)^2&=&(-2)^2+2*(-2)*(-4i)+(-4i)^2\\
&=& 4+8i+16i^2\\
&=&4+8i-16\\
&=&-12+8i
\end{array}$$
+11 $${{\mathtt{xi}}}^{{\mathtt{2}}} = {\mathtt{\,-\,}}\left({{\mathtt{x}}}^{{\mathtt{2}}}\right) \Rightarrow \left\{ \begin{array}{l}{\mathtt{xi}} = {\mathtt{\,-\,}}\left({i}{\mathtt{\,\times\,}}{\mathtt{x}}\right)\\
{\mathtt{xi}} = {i}{\mathtt{\,\times\,}}{\mathtt{x}}\\
\end{array} \right\}$$
+118609 It is this: (- 2 - 4i) ^ 2
Is the result but not be as it is the procedure for the exercise! Ayudaa
by Anonymous (3 hours ago)
This is just a perfect square
$$(a+b)^2=a^2+2ab+b^2$$
--------------------------------
$$\begin{array}{rll}
(-2-4i)^2&=&(-2)^2+2*(-2)*(-4i)+(-4i)^2\\
&=& 4+8i+16i^2\\
&=&4+8i-16\\
&=&-12+8i
\end{array}$$
