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find 3 positive consecutive integers such that the product of the first and the third integer is 17 more than three times the second integer

 Mar 11, 2021
 #1
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x ( x + 2)  = 3(x + 1)  + 17           simplify

 

x^2  + 2x   =  3x  + 20         rearrange   as

 

x^2 - x  -20   =  0       factor as

 

(x -5) ( x + 4)   =20

 

The first factor is what we need

 

 

x  - 5 =    0

 

x = 5

 

x + 1  = 6

 

x + 2 =  7

 

 

Proof

 

5*7  = 3 (6) + 17

 

35  =  18  + 17    (true)

 

 

cool cool cool

 Mar 11, 2021

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