Consider a triangle where A = 30° a = 1.3cm b = 0.6cm.
Use the law of sines to find sin(B). Round the answer to 2 decimal places.
sin B / b = sin A / a
sin B / .6 = sin (30) / 1.3 multiply by .6 on both sides
sin B = (.6 / 1.3) sin (30)
sin B = (.6 / 1.3) (1/2)
sin B = (.3 / 1.3) take the sine inverse
arcsin (.3 / 1.3) = B ≈ 13.34°
+295 
