Consider the system of equations

5x-2y=16

15x-7y=51

Multiply the first equation by some constant, so that in the resulting equation, the coefficient of matches the coefficient of in the second equation.

Enter the entire equation that results from multiply

Guest Oct 9, 2018

#1**+2 **

The question never specifies which coefficient I am matching. Am I matching the coefficient of the "x" or the coefficient of the "y?"

I guess I will answer both questions.

The first equation \(5x-2y=16\), the coefficient of *x *is 5. The coefficient of *x *in the second equation is 15. Therefore, the constant necessary to multiply the first equation is 3.

The first equation \(5x-2y=16\) , the coefficient of * y *is -2. The coefficient of *y *in the second equation is -7. Therefore, the constant necessary to multiply the first equation is 7/2 or 3.5.

TheXSquaredFactor Oct 9, 2018

#1**+2 **

Best Answer

The question never specifies which coefficient I am matching. Am I matching the coefficient of the "x" or the coefficient of the "y?"

I guess I will answer both questions.

The first equation \(5x-2y=16\), the coefficient of *x *is 5. The coefficient of *x *in the second equation is 15. Therefore, the constant necessary to multiply the first equation is 3.

The first equation \(5x-2y=16\) , the coefficient of * y *is -2. The coefficient of *y *in the second equation is -7. Therefore, the constant necessary to multiply the first equation is 7/2 or 3.5.

TheXSquaredFactor Oct 9, 2018