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Consider this system of equations:

2/3x+ 3/5y=12 (equation A)

5/2y3x=6(equation B)

The expression that gives the value of x is                       .
The solution for the system of equations is                            .

 

                      5a/3+ 2b/5      3a/5 5b/25a/2+ 3b/55a/3 2b/53a/2+ b/5                            (1118/47, 396/47)   (33/13, 50/13)(99/13, 150/13)(8,12)

 Jan 24, 2018
edited by SpaceModo  Jan 24, 2018
 #1
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+2

(2/3)x  + (3/5)y  =  12

-3x   + (5/2)y  =  6

 

Mutiply  the first equation through by the common denominator of 3 and 5 = 15

Multiply the second equation through by 2

 

So we have

 

10x  +  9y   =  180    multipy through by 6  =   60x + 54y  = 1080    (1)

-6x  +  5y      =  12  multiply through   by 10  =   -60x  + 50y  =   120    (2)

 

Add (1)  and (2)

 

104y  =  1200     divide by  104

 

y =   1200/104 =   600/52  =  150 / 13

 

Obviously, only one answer has a "y" answer that  =  150/13.....so that must be the correct one

 

 

cool cool cool

 Jan 24, 2018

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