Consider y=log2(x−3). When y=5,x=?

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Consider y=log2(x−3). When y=5,x=?

Guest Feb 16, 2015

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Best Answer

+128707

+5

y=log2(x−3). When y=5,x=?

5 = log₂ (x - 3) says, in exponential terms

2^5 = x - 3 add 3 to both sides

32 + 3 = x = 35

CPhill Feb 16, 2015

1⁺⁰ Answers

+128707

+5

Best Answer

y=log2(x−3). When y=5,x=?

5 = log₂ (x - 3) says, in exponential terms

2^5 = x - 3 add 3 to both sides

32 + 3 = x = 35

CPhill Feb 16, 2015

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