What is the constant term of the expansion of (6x + 1/(2x))^8?
( 6x + 1 / (2x) )^8
The constant term is
C (8,4) (6x)^4 * (1/ (2x) )^4 =
70 (6x)^4 (1/ (2x) )^4 =
70 * 1296x^4 * 1/ (16 x^4) =
70 * 81 =
5670
