+113 A 10cm by 12cm rectangular container contains some water. When a solid metal cube with volume 216cm3 is placed in the water, the water level comes up level with the top of the cube. In cm, what was the original height of the water in the container?
A) 3.8
B) 4.25
C) 4.5
D) 3.9
E) 4.2
+9481 the side length of the cube = \(\sqrt[3]{216}\) cm = 6 cm
So we know...
volume of water + volume of cube = 10 * 12 * 6 cm3 = 720 cm3
volume of water + 216 cm3 = 720 cm3
volume of water = 504 cm3
10 cm * 12 cm * original height = 504 cm3
original height = 504 / 120 cm = 4.2 cm 
+9481 the side length of the cube = \(\sqrt[3]{216}\) cm = 6 cm
So we know...
volume of water + volume of cube = 10 * 12 * 6 cm3 = 720 cm3
volume of water + 216 cm3 = 720 cm3
volume of water = 504 cm3
10 cm * 12 cm * original height = 504 cm3
original height = 504 / 120 cm = 4.2 cm
