Convert the Cartesian coordinate (2,3) to polar coordinates, 0 le theta lt 2pi, \quad r>0

I am not sure about the 'best, way to do this but

$$\\r=\sqrt{4+9}=\sqrt{13}\\ tan\theta=3/2\\$$

$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{tan}}^{\!\!\mathtt{-1}}{\left({\mathtt{1.5}}\right)} = {\mathtt{56.309\: \!932\: \!474\: \!02^{\circ}}}$$

$$(2,3)\approx(\sqrt{13}, 56.3^0)$$

I think that is correct :)

Good job, Melody.....!!!!...you are correct....