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Convert 2i to polar form

 Dec 14, 2018
edited by Guest  Dec 14, 2018

Best Answer 

 #6
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\(y=2^i\\ ln\;y=ln\;2^i\\ ln\;y=i\;ln\;2\\ y=e^{i\;ln2}\\ y=cos(ln2)+isin(ln2)\)

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 Dec 14, 2018
 #1
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Polar form is \( z=r(cosθ+i(sinθ))\) for some complex number \(z\)

 Dec 14, 2018
 #2
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I know that but how do you convert 2^i to polar form?

Guest Dec 14, 2018
 #3
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I am not entirely sure, but I looked at this website to understand polar form. The website also gives an example of an irrational complex number in polar form.

PartialMathematician  Dec 14, 2018
 #4
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Also here

PartialMathematician  Dec 14, 2018
 #5
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I know how to convert standard complex numbers in the form of a+bi to polar form. What confuses me here is the fact that 2^i is not in the standard complex number form

Guest Dec 14, 2018
 #6
avatar+3 
+2
Best Answer

\(y=2^i\\ ln\;y=ln\;2^i\\ ln\;y=i\;ln\;2\\ y=e^{i\;ln2}\\ y=cos(ln2)+isin(ln2)\)

ReallyWC Dec 14, 2018
 #7
avatar+812 
0

Well, there you have it.

PartialMathematician  Dec 14, 2018

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