Convert (x−3)^2+y^2=9 to polar form.
r = ____ ____
(x -3)^2 +y^2 = 9
( rcos θ - 3)^2 + (rsinθ)^2 = 9
r^2cos^2θ - 6rcosθ + 9 + r^2 sin^2θ = 9 subtract 9 from both sides
r^2 ( sin^2 θ + cos ^2 θ) - 6r cosθ = 0
r^2 (1) = 6r cosθ divide out r
r = 6cosθ
