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How do you get this function: h(x) = −2(x − 2)^2 + 2, to turn into this function: h(x)−2x^2 + 8x − 6?

Show work please.

Absolutezero  Jun 2, 2017

Best Answer 

 #1
avatar+17613 
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h(x)  =  -2(x - 2)2 + 2

h(x)  =  -2(x - 2)(x - 2) + 2

h(x)  =  -2(x2 - 2x - 2x + 4) + 2                   [Use FOIL]

h(x)  =  -2(x2 - 4x + 4) + 2                          [Simplify]

h(x)  =  -2x2 + 8x - 8 + 2                             [Distribute the -2] 

h(x)  =  -2x2 + 8x - 6                                   [Simplify]

geno3141  Jun 2, 2017
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1+0 Answers

 #1
avatar+17613 
+1
Best Answer

h(x)  =  -2(x - 2)2 + 2

h(x)  =  -2(x - 2)(x - 2) + 2

h(x)  =  -2(x2 - 2x - 2x + 4) + 2                   [Use FOIL]

h(x)  =  -2(x2 - 4x + 4) + 2                          [Simplify]

h(x)  =  -2x2 + 8x - 8 + 2                             [Distribute the -2] 

h(x)  =  -2x2 + 8x - 6                                   [Simplify]

geno3141  Jun 2, 2017

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