Find the constant term in the expansion of (2z−1√z)9
Check out this problem! I was doing homework, and this was one of the problems!
The solution was pretty cool. also, do not scroll down if you don't want to see the answer.
ANSWER:
formula:
(9k)(2z)9−k(−1√z)k=(9k)(−1)k29−kz9−kzk/2.
Answer:
(96)(−1)629−6=672