+31 Find the constant term in the expansion of \( \Big(2z - \frac{1}{\sqrt{z}}\Big)^9\)
Check out this problem! I was doing homework, and this was one of the problems!
The solution was pretty cool. also, do not scroll down if you don't want to see the answer.
ANSWER:
formula:
\(\binom{9}{k} (2z)^{9-k}\Big(-\frac{1}{\sqrt{z}}\Big)^k = \binom{9}{k}(-1)^k 2^{9 - k} \frac{z^{9-k}}{z^{k/2}}.\)
Answer:
\(\binom{9}{6} (-1)^6 2^{9 - 6} = \boxed{672} \)
