An ordinary 6-sided die has a number on each face from 1 to 6 (each number appears on one face). How many ways can I paint two faces of a die blue, so that the product of the numbers on the painted faces isn't equal to 6?

ant101 Dec 10, 2018

#1**+2 **

1 x 6 = 6

3 x 2 = 6 You have to paint one number from EACH pair

So you have to paint 1 3 1 2 6 3 6 2

4 ways

ElectricPavlov Dec 10, 2018

#2**+1 **

We have the following number of possible sets of numbers.....we have six numbers and we want to choose any two of them....so....

C(6,2) = 15 sets

These are

(1,2) (1,3) (1,4) (1, 5) (1,6)

(2, 3) (2,4) (2, 5) (2, 6)

(3,4) (3,5) (3,6)

(4, 5) ( 4, 6)

(5, 6)

Note, Ant, that only two of them have a product of six

So.....thirteen don't

CPhill Dec 11, 2018