+885 An ordinary 6-sided die has a number on each face from 1 to 6 (each number appears on one face). How many ways can I paint two faces of a die blue, so that the product of the numbers on the painted faces isn't equal to 6?
+37146 1 x 6 = 6
3 x 2 = 6 You have to paint one number from EACH pair
So you have to paint 1 3 1 2 6 3 6 2
4 ways
+129852 We have the following number of possible sets of numbers.....we have six numbers and we want to choose any two of them....so....
C(6,2) = 15 sets
These are
(1,2) (1,3) (1,4) (1, 5) (1,6)
(2, 3) (2,4) (2, 5) (2, 6)
(3,4) (3,5) (3,6)
(4, 5) ( 4, 6)
(5, 6)
Note, Ant, that only two of them have a product of six
So.....thirteen don't
