Figure ABCD has vertices A(−3, 2), B(2, 2), C(2, −4), and D(−3, −2). What is the area of figure ABCD?

Sunrisesk8r Aug 1, 2017

#2**+1 **

Look at the following diagram :

If you include point E as (2, - 2)....we have a rectangle ABED whose width = AB = 5 and height = BE = 4

So...its total area is just width * height = 5 * 4 = 20 sq units

And triangle DEC has a base DE = 5 and a height EC = 2....so its area is [ b * h ] / 2 = [ 5 * 2 ] / 2 = 10 / 2 = 5 sq units

So....the toal area is just 20 + 5 = 25 sq units

CPhill Aug 1, 2017

#3**0 **

Graphing is technically not necessary to solve the problem as you could be aware of the conditions of the different types of quadrilaterals, but doing so helps the solving process immensely.

TheXSquaredFactor Aug 1, 2017