Find the point Q along the directed line segment that divides into the ratio 2:3

Guest Jul 13, 2020

#2**+1 **

I'll assume it is line AB where AQ : QB is 2:3

There is a formula for this that is easy to use but I can never remember it.

So I will try to work it out logically. The triangle helps a lot.

CB is 6 units, divided by 5 is 1.2units, times 2 is 2.4units -4+2.4=-1.6 that is the x value

AC is 10 units, divide by 5 is 2 units multiply by 2 is 4 units, 7-4=3 this is the y value

So the point is (-1.6,3)

Melody Jul 13, 2020