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Find the point Q along the directed line segment that divides into the ratio 2:3

 

 Jul 13, 2020
 #1
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Is this the correct diagram?   Which line segment?    cheeky

 Jul 13, 2020
 #2
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I'll assume it is line AB where   AQ : QB  is   2:3

There is a formula for this that is easy to use but I can never remember it.

So I will try to work it out logically.  The triangle helps a lot.

 

CB is 6 units, divided by  5 is 1.2units, times 2 is 2.4units    -4+2.4=-1.6  that is the x value

 

AC is 10 units, divide by 5 is 2 units multiply by 2 is 4 units,     7-4=3    this is the y value

 

So the point is (-1.6,3)

 Jul 13, 2020

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