+128475 3x^2 - 7x - 6 (3x + 2) ( x - 3) 3x + 2
f(x ) = ____________ = _____________ = _______ (1)
2x^2 - 5x - 3 (2x + 1) ( x -3) 2x + 1
The x coordinate of the "hole" can be found as x - 3 = 0 ⇒ x = 3
To find the y coordinate of the hole......sub this x value into (1) and we have
3(3) + 2 11
_______ = ____
2(3) + 1 7
So....the "hole" occurs at (3, 11/7)
See the graph, here :
https://www.desmos.com/calculator/7mdt3lommd
thank you 
